Returns the specified part of a given date.
DatePart(interval, date[, firstdayofweek[, firstweekofyear]])
The interval argument can have the following values:
| Setting | Description |
|---|---|
| yyyy | Year |
| q | Quarter |
| m | Month |
| y | Day of year |
| d | Day |
| w | Weekday |
| ww | Week of year |
| h | Hour |
| n | Minute |
| s | Second |
The firstdayofweek argument can have the following values:
| Constant | Value | Description |
|---|---|---|
| vbUseSystemDayOfWeek | 0 | Use National Language Support (NLS) API setting. |
| vbSunday | 1 | Sunday (default) |
| vbMonday | 2 | Monday |
| vbTuesday | 3 | Tuesday |
| vbWednesday | 4 | Wednesday |
| vbThursday | 5 | Thursday |
| vbFriday | 6 | Friday |
| vbSaturday | 7 | Saturday |
The firstweekofyear argument can have the following values:
| Constant | Value | Description |
|---|---|---|
| vbUseSystem | 0 | Use National Language Support (NLS) API setting. |
| vbFirstJan1 | 1 | Start with the week in which January 1 occurs (default). |
| vbFirstFourDays | 2 | Start with the week that has at least four days in the new year. |
| vbFirstFullWeek | 3 | Start with the first full week of the new year. |
You can use the DatePart function to evaluate a date and return a specific interval of time. For example, you might use DatePart to calculate the day of the week or the current hour.
The firstdayofweek argument affects calculations that use the "w" and "ww" interval symbols.
If date is a date literal, the specified year becomes a permanent part of that date. However, if date is enclosed in quotation marks (" "), and you omit the year, the current year is inserted in your code each time the date expression is evaluated. This makes it possible to write code that can be used in different years.
This example takes a date and, using the DatePart function, displays the quarter of the year in which it occurs.
Function GetQuarter(TheDate) GetQuarter =DatePart("q",TheDate)End Function